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The thickness of a steel plate with material strength coefficient of $210\: MPa$, has to be reduced from $20\: mm$ to $15\: mm$ in a single pass in a two-high rolling mill with a roll radius of $450\: mm$  and rolling velocity of $28\: m/min$. If the plate has a width of $200\: mm$ and its strain hardening exponent, $n$ is $0.25$, the rolling force required for the operation is ________ $kN$ (round off to $2$ decimal places).

Note: $\text{Average Flow Stress  = Material Strength Coefficient}\times \dfrac{\left (\text{True Strain} \right )^{n}}{(1+n)}$
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