A force of $400$ N is applied to the brake drum of $0.5$ m diameter in a band-brake system as shown in the figure, where the wrapping angle is $180^{\circ}$. If the coefficient of friction between the drum and the band is $0.25$, the braking torque applied, in N.m is
- $100.6$
- $54.4$
- $22.1$
- $15.7$